U3d 的 webplayer 的截图实现.txt

1. 首先是建一个 C# 类

using System;
using UnityEngine;
using System.Collections;
public class PostPng
{
    public static string UploadUrl = http://127.0.0.1/getpng.php;
    public static void UploadPNG(MonoBehaviour thread, string fileName, Action<bool> result)
    {
        thread.StartCoroutine(UploadPNG(fileName, result));
    }
    
    private static IEnumerator UploadPNG(string fileName, Action<bool> result)
    {
        yield return new WaitForEndOfFrame();
        int width = Screen.width;
        int height = Screen.height;
        Texture2D tex = new Texture2D(width, height, TextureFormat.RGB24, false);
        tex.ReadPixels(new Rect(0, 0, width, height), 0, 0);
        tex.Apply();
        byte[] bytes = tex.EncodeToPNG();
        GameObject.Destroy(tex);
        WWWForm form = new WWWForm();
        form.AddField("enctype", "multipart/form-data");
        form.AddBinaryData("PngUpload", bytes, fileName, "image/png");
        WWW post = new WWW(UploadUrl , form);
        yield return post;
        if (string.IsNullOrEmpty(post.error) && result != null)
        {
            result(true);
        }
        else
        {
            result(false);
        }
        post.Dispose();
    }
}

2. 再建一个 Cube,再建一个 C# 脚本

OnGUI()
{

    if (GUI.Button(new Rect(440, Screen.height – 25, 65, 23), "Snapshot"))
    {
        LoadHelp.UploadPNG(this, "Snapshot", delegate(bool result)
        {
            if (result)
            {
                Application.ExternalEval("alert('ok')");
            }
        });
    }
}

3. 最后要建立一个 接受图片上传的程序，用什么取决于你的web服务器 我这里用的是 php：

<?php
$filename = "";
$field = "PngUpload";
$pngfolder = "snapshot/";
if ($_FILES[$field]["error"] > 0)
{
    echo "Error: " . $_FILES[$field]["error"];
}
else
{
    $filename = $pngfolder . $_FILES[$field]["name"] . ".png";
    move_uploaded_file($_FILES[$field]["tmp_name"], $filename);
    echo("ok");
}
?>